What is the perimeter of a triangle with corners at (7 ,3 ), (4 ,5 ), and (3 ,3 )?

Jan 3, 2017

$2 p = \sqrt{5} + \sqrt{13} + 4$

Explanation:

$A = \left(7 , 3\right) , B = \left(4 , 5\right) , C = \left(3 , 3\right)$

$| A B | = \sqrt{{\left(7 - 4\right)}^{2} + {\left(3 - 5\right)}^{2}} = \sqrt{9 + 4} = \sqrt{13}$

$A C : y = 3 R i g h t a r r o w | A C | = | 7 - 3 | = 4$

$| B C | = \sqrt{{\left(4 - 3\right)}^{2} + {\left(5 - 3\right)}^{2}} = \sqrt{1 + 4} = \sqrt{5}$