Question

What is the perimeter of a triangle with corners at `(7 ,9 )`, `(8, 2 )`, and `(9 ,2 )`?

Answer 1

`=15.35`

Explanation:

So sides of the triangle with corners at `(7,9),(8,2), and (9,2)` are as follows
Side `1`
`sqrt((9-2)^2+(8-7)^2)`
`=sqrt(7^2+1^2`
`=sqrt(49+1)`
`=sqrt50`
`=7.07`
Side `2`
`=sqrt((9-8)^2+(2-2)^2`
`=sqrt(1^2+0^2`
`=sqrt(1+0)`
`=sqrt1`
`=1`
Side `3`
`sqrt((9-2)^2+(9-7)^2)`
`=sqrt(7^2+2^2`
`=sqrt(49+4)`
`=sqrt53`
`=7.28`
So perimeter `=7.07+1+7.28=15.35`