Question

What is the perimeter of a triangle with corners at `(8 ,5 )`, `(9 ,9 )`, and `(3 ,4 )`?

Answer 1

Perimeter of the triangle is `AB+BC+CA=17.03 (2dp)`

Explanation:

Let `A(8,5) B(9,9) C(3,4)`are the vertices of the triangle. Sides `AB=sqrt((9-5)^2+(9-8)^2) =sqrt 17=4.12 ; BC= sqrt((4-9)^2+(3-9)^2) =sqrt 61 =7.81 ; CA= sqrt((5-4)^2+(8-3)^2) =sqrt 26=5.1 :.`Perimeter of the triangle is `AB+BC+CA=17.03 (2dp)`[Ans]