# What is the perimeter of a triangle with corners at (9 ,5 ), (6 , 2 ), and (5 ,7 )?

Oct 8, 2017

Perimeter of the triangle $= 27.05$

#### Explanation:

Length of sides :
$A B = \sqrt{{3}^{2} + {3}^{2}} = \sqrt{18} = 3 \sqrt{2}$
$B C = \sqrt{{5}^{2} + {\left(- 1\right)}^{2}} = \sqrt{26}$
$C A = \sqrt{{2}^{2} + {\left(- 4\right)}^{2}} = \sqrt{20} = 2 \sqrt{5}$
Perimeter = $3 \sqrt{2} + \sqrt{26} + 2 \sqrt{5}$
$= 27.05$