What is the period of #y = -4cos(3x+pi/2) + 2#?

1 Answer
Jul 10, 2017

#"period "=(2pi)/3#

Explanation:

#"the standard form of the cosine function is"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b," vertical shift "=d#

#"here " a=-4,b=3,c=pi/2" and " d=2#

#rArr"period "=(2pi)/3#