# What is the pH of a 0.00162 M NaOH solution?

So we calculate $p O H$, i.e. $p O H = - {\log}_{10} \left(1.62 \times {10}^{-} 3\right) = 2.79$. This is by definition of $p$ function.
But $p H = 14 - 2.79$ from the above, so pH=??