What is the pH of a 6.2 x 10-2 mol/L solution of nitric acid?

1 Answer
Jun 5, 2017

Answer:

#pH=-log_10[H_3O^+]=1.21#

Explanation:

#pH=-log_10[H_3O^+]#

We know that nitric acid is a moderately strong acid for which protonolysis of the water solvent is relatively complete, i.e. the given equilibrium lies to the right...........

#HNO_3(aq) + H_2O(l) rarr H_3O^+ + NO_3^-#

That is the solution is stoichiometric in #H_3O^+#.

And we simply take #log_10#............

#-log_10(6.2xx10^-2)=-(-1.207)=1.21#.

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