What is the pH of a solution with [H+]= #2.3 x 10^-6#?

1 Answer
Jul 8, 2016

Answer:

#pH=5.64#

Explanation:

#pH=-log_10[H_3O^+]#

#=-log_(10){2.3xx10^-6}#

#=-{-5.64}#

#=5.64#

If you are not confident with the logarithmic function please voice your concern. See here for the relationship between #pH# and #pOH# in aqueous solution.