What is the pH of an aqueous solution if the [#H^+#]=0.000001?

1 Answer
Oct 3, 2016

Answer:

#pH=6#

Explanation:

#pH=-log_10[H_3O^+]#

But if #[H^+]# or #[H_3O^+]# #=# #0.000001*mol*L^-1#;

then #pH# #=# #-log_10(0.000001)# #=# #-log_10(10^-6)#.

Now, by definition, #log_10(10^-6)# #=# #-6#.

Thus #pH=-(-6)# #=# #6#

This is slightly acid, and #[H_3O^+]# is #10xx[HO^-]#.

If #[H_3O^+]# #=# #0.001*mol*L^-1#, what is #pH#?