What is the #pOH# of a #5.6*10^-5# #M# solution of cesium hydroxide?

1 Answer
Jul 2, 2016

Answer:

#pOH=4.25#

Explanation:

#CsOH rarr Cs^(+) + HO^-#.

The solution is stoichiometric in #CsOH(aq)#.

#pOH=-log_10[HO^-]#

#=# #-log_10(5.6xx10^-5)#

#=# #-log_10(5.6xx10^-5)# #=# #-(-4.25)#

#=# #4.25#

What is #pH# of this solution? You should not need a calculator.