# What is the pOH of a 5.6*10^-5 M solution of cesium hydroxide?

Jul 2, 2016

$p O H = 4.25$

#### Explanation:

$C s O H \rightarrow C {s}^{+} + H {O}^{-}$.

The solution is stoichiometric in $C s O H \left(a q\right)$.

$p O H = - {\log}_{10} \left[H {O}^{-}\right]$

$=$ $- {\log}_{10} \left(5.6 \times {10}^{-} 5\right)$

$=$ $- {\log}_{10} \left(5.6 \times {10}^{-} 5\right)$ $=$ $- \left(- 4.25\right)$

$=$ $4.25$

What is $p H$ of this solution? You should not need a calculator.