What is the #pOH# of a #5.6*10^-5# #M# solution of cesium hydroxide?

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Answer 1 · 2016-07-02T13:15:09

#pOH=4.25#

#CsOH rarr Cs^(+) + HO^-#.

The solution is stoichiometric in #CsOH(aq)#.

#pOH=-log_10[HO^-]#

#=# #-log_10(5.6xx10^-5)#

#=# #-log_10(5.6xx10^-5)# #=# #-(-4.25)#

#=# #4.25#

What is #pH# of this solution? You should not need a calculator.