# What is the pOH of a solution with an [OH-] concentration of 9.2 x 10^-11 M?

$p O H = 10.0$
$p O H = - {\log}_{10} \left[H {O}^{-}\right]$.
If $\left[H {O}^{-}\right] = 9.2 \times {10}^{-} 11 \cdot m o l \cdot {L}^{-} 1$, then $p O H = - {\log}_{10} \left[9.2 \times {10}^{-} 11\right] = 10.0$
What is $p H$ of this solution?