Question

What is the pOH of a solution with an [OH-] concentration of `9.2 x 10^-11` M?

Answer 1

`pOH=10.0`

Explanation:

`pOH=-log_10[HO^-]`.

If `[HO^-]=9.2xx10^-11*mol*L^-1`, then `pOH=-log_(10)[9.2xx10^-11]=10.0`

What is `pH` of this solution?