# What is the pressure of 0.250 mol of air contained in a balloon having a volume of 1.50 L at 35.0 °C?

Well, if we assume ideal behaviour...........I get a pressure of under $5 \cdot a t m$.
$P = \frac{n R T}{V} = \frac{0.250 \cdot m o l \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 308.1 \cdot K}{1.50 \cdot L}$
=??atm..........