Question

What is the pressure of 0.250 mol of air contained in a balloon having a volume of 1.50 L at 35.0 °C?

Answer 1

Well, if we assume ideal behaviour...........I get a pressure of under `5*atm`.

Explanation:

`P=(nRT)/V=(0.250*molxx0.0821*(L*atm)/(K*mol)xx308.1*K)/(1.50*L)`

`=??atm..........`