What is the prime factorization of 125?

1 Answer
Oct 29, 2016

The prime factorization of #125# is #5^3#.

Explanation:

To find the prime factorization, divide #125# by only prime numbers. Remember that prime numbers are whole numbers greater than #1# that are only evenly divisible by themselves and #1#.
{#2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53#, etc.}

Since #125# ends in #5#, it is evenly divisible by #5#, which is a prime number. (How convenient!)

#125 -: 5 = 25#

#25# now has to be factored into its prime factors.

#25 = 5 * 5#

So, the prime factorization of #125# is

#125 = 5*5*5 = 5 ^3#