What is the prime factorization of 125?

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What is the prime factorization of 125?

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Answer 1 · 2016-10-29T01:43:06

The prime factorization of $125$ $125$ is $5^{3}$ $5^3$ .

Explanation:

To find the prime factorization, divide $125$ $125$ by only prime numbers. Remember that prime numbers are whole numbers greater than $1$ $1$ that are only evenly divisible by themselves and $1$ $1$ .
{ $2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53$ $2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53$ , etc.}

Since $125$ $125$ ends in $5$ $5$ , it is evenly divisible by $5$ $5$ , which is a prime number. (How convenient!)

$125 \div 5 = 25$ $125 -: 5 = 25$

$25$ $25$ now has to be factored into its prime factors.

$25 = 5 \cdot 5$ $25 = 5 * 5$

So, the prime factorization of $125$ $125$ is

$125 = 5 \cdot 5 \cdot 5 = 5^{3}$ $125 = 5*5*5 = 5 ^3$

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What is the prime factorization of 125?

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