#P["odds for one pair"] =
C(5,2)(52/52)(3/52)(48/50)(44/49)(40/48) = 0.422569 = 42.2569 %
# #
"A pair of aces is 1/13-th of this"
= 0.422569 / 13
= 0.0325
#
#
""
" (on the condition that there are not more than 2 aces "
" and that there is no pair or three of a kind of another rank)"#