# What is the probability that you draw 3 cards and you selected 3 aces from a deck of 52 cards?

$\frac{1}{11050} \cong 9 \times {10}^{- 5}$

#### Explanation:

There are 4 aces in a standard deck of 52 cards.

If we draw a single card, the chance we get an ace is:

$\frac{4}{52}$

Now let's draw a second card. We've already pulled one ace, so there are 3 left, and there are now 51 cards left, so the chance of pulling 2 aces on 2 draws is:

$\frac{4}{52} \times \frac{3}{51}$

And following this same logic with the third draw to get a third ace, we have:

$\frac{4}{52} \times \frac{3}{51} \times \frac{2}{50} = \frac{12}{132600} = \frac{1}{11050} \cong 9 \times {10}^{- 5}$