Dec 7, 2017

See a solution process below:

#### Explanation:

First, we can write and then rewrite this as;

$2 \sqrt{7} \cdot 3 \sqrt{5} \implies$

$\left(2 \cdot 3\right) \left(\sqrt{7} \cdot \sqrt{5}\right) \implies$

$6 \left(\sqrt{7} \cdot \sqrt{5}\right)$

Now, we can use this rule for radicals to multiply the radicals:

$\sqrt{\textcolor{red}{a}} \cdot \sqrt{\textcolor{b l u e}{b}} = \sqrt{\textcolor{red}{a} \cdot \textcolor{b l u e}{b}}$

$6 \left(\sqrt{\textcolor{red}{7}} \cdot \sqrt{\textcolor{b l u e}{5}}\right) \implies$

$6 \sqrt{\textcolor{red}{7} \cdot \textcolor{b l u e}{5}} \implies$

$6 \sqrt{35}$