Question

What is the product of the following reaction? 1)`CH_3 OH + OH^(-) rarr` 2)`NH_4 ^(+) + OH^(-) rarr`

Answer 1

These are ostensibly acid-base reactions....

Explanation:

For ammonium we could write....

`NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l)`

For methanol, the acid base reaction would proceed to a much lesser degree....

`H_3COH + HO^(-)rightleftharpoonsH_3CO^(-) + H_2O(l)`

...this equilibrium lies strongly to the left....