Question

What is the quadratic formula of `v^2 + 14v + 33 = 0`?

Answer 1

see a solution process below;

Explanation:

The quadratic formula is given below;

`v = (-b +- sqrt(b^2 - 4ac))/(2a)`

Given;

`v^2 + 14v + 33 = 0`

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`ax^2 + bx + c = 0`

Where;

`a = 1`

`b = +14`

`c = +33`

Substituting it into the formula;

`v = (-(+14) +- sqrt(14^2 - 4(1)(33)))/(2(1))`

`v = (-14 +- sqrt(196 - 132))/2`

`v = (-14 +- sqrt64)/2`

`v = (-14 +- 8)/2`

`v = (-14 + 8)/2 or v = (-14 - 8)/2`

`v = (-6)/2 or v = (-22)/2`

`v = -3 or v = -11`