# What is the quotient of y − 5 divided by 2y^2 − 7y − 15?

Mar 31, 2016

$\left(y - 5\right) \div \left(2 {y}^{2} - 7 - 15\right)$ results in a quotient of $0$ and a remainder of $\left(y - 5\right)$

#### Explanation:

Perhaps the question should have been
$\textcolor{w h i t e}{\text{XXX}} \left(2 {y}^{2} - 7 y - 15\right) \div \left(y - 5\right)$

In which case:
$\textcolor{w h i t e}{\text{XXXX}} 2 y + 3$
$y - 5 \text{)} \overline{2 {y}^{2} - 7 y - 15}$
$\textcolor{w h i t e}{\text{XXXx}} \underline{2 {y}^{2} - 10 y}$
$\textcolor{w h i t e}{\text{XXXXXXX}} 3 y - 15$
$\textcolor{w h i t e}{\text{XXXXXXX}} \underline{3 y - 15}$
$\textcolor{w h i t e}{\text{XXXXXXXXXXX}} 0$