What is the radius of convergence of #sum_1^oo (x-3)/n^(11/10)#?
1 Answer
Nov 29, 2015
Infinite
Explanation:
#int_1^oo 1/t^(11/10) dt=int_1^oo t^(-11/10) dt=[-10t^(-1/10)]_1^oo=10#
So
So