Question

What is the radius of the circle whose equation is `(x+3)^2+(y-7)^2=289`?

Answer 1

Radius`=17`.

Explanation:

If `(h,k)` is centre and `r` radius, the eqn. of circle is `: (x-h)^2+(y-k)^2=r^2`

Comparing with the given eqn. of circle, we find, `r^2=289`

Hence, radius `r` is `17`