What is the radius of the circle with the equation #(x-3)^2+(y+4)^2=16#?
1 Answer
Sep 18, 2016
radius = 4
Explanation:
The standard form of the equation of a circle is.
#color(red)(bar(ul(|color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))#
where (a ,b) are the coordinates of the centre and r, the radius.
#(x-3)^2+(y+4)^2=16" is in this form"# and by comparison with the standard form.
a = 3 , b= - 4 and
#r^2=16rArrr=sqrt16=4#
