Question

What is the range of an arrow shot horizontally at 85.3 m/s if it is initially 1.50 m above the ground?

Answer 1

`47.2"m"`

Explanation:

Use the vertical component of motion to get the time of flight:

`s=1/2"g"t^2`

`:.t^2=(2s)/g=(2xx1.5)/(9.8)=0.306`

`:.t=sqrt(0.306)=0.55"s"`

The horizontal component of velocity is constant so:

`s=vxxt=85.3xx0.55=47.2"m"`