Question

What is the rate of growth, as a percent, for the function `d(x) = 23(1.0032)^x`?

Answer 1

See explanation

Explanation:

Matching this to the standard form for compound interest:

`d_2(x)=23(100/100+0.32/100)^x`

`d_2(x)=23(1+0.32/100)^x`

giving `0.32%` Per calculation cycle