What is the ratio of the moles of conjugate base to the moles of acid if the pH is 5.29 and the pKa is 5.150?

Nov 5, 2016

$\frac{\left[{A}^{-}\right]}{\left[H A\right]} = {10}^{0.14}$ $=$ ??

Explanation:

$p H = p {K}_{a} + {\log}_{10} \left(\frac{\left[{A}^{-}\right]}{\left[H A\right]}\right)$

i.e. $5.29 = 5.150 + {\log}_{10} \left(\frac{\left[{A}^{-}\right]}{\left[H A\right]}\right)$

Thus ${\log}_{10} \left(\frac{\left[{A}^{-}\right]}{\left[H A\right]}\right) = 0.14$.

$\frac{\left[{A}^{-}\right]}{\left[H A\right]} = {10}^{0.14}$ $=$ ??