Question

What is the remainder when `(2x^3+4x^2-32x+18)-:(x+3)`?

Answer 1

`96`

Explanation:

Let `f(x) = 2x^3+4x^2-32x+18`

The remainder when `f(x)` is divided by `(x-a)` is `f(a)`.

So when divide by `(x+3) = (x-(-3))` the remainder is:

`f(-3) = 2(-27)+4(9)-32(-3)+18`

`=-54+36+96+18 = 96`