# What is the remainder when (2x^3 – 8x^2 + 6x – 6) ÷ (x – 4)?

The Remainder Theorem states that the remainder when a polynomial $P \left(x\right)$ is divided by $x - a$ is equal to $P \left(a\right)$.
Applying this, we get that the remainder is just $2 {\left(4\right)}^{3} - 8 {\left(4\right)}^{2} + 6 \left(4\right) - 6 = 18$