# What is the simplest form of sqrt(80x7y5)?

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Feb 10, 2018

#### Answer:

$4 {x}^{3} {y}^{2} \sqrt{5 x y}$

#### Explanation:

I'm assuming you meant $\sqrt{80 {x}^{7} {y}^{5}}$
If so, you take the square root of 80, shown as..

$\sqrt{80}$
$\sqrt{4 \cdot 4 \cdot 5}$
$2 \cdot 2 \sqrt{5}$
$4 \sqrt{5}$

then we divide the powers by 2, if they're even, or if they're odd, subtract one (which will stay inside the radical) then divide by 2

for $x$:
$\sqrt{{x}^{7}}$
sqrt(x^6*x
${x}^{3} \sqrt{x}$

and for $y$:
$\sqrt{{y}^{5}}$
$\sqrt{{y}^{4} \cdot y}$
${y}^{2} \sqrt{y}$

then multiply the answers together, and there you have it

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