What is the simplest form of sqrt(80x7y5)?

1 Answer
Feb 9, 2018

4x^3y^2sqrt(5xy)

Explanation:

I'm assuming you meant sqrt(80x^(7)y^(5))
If so, you take the square root of 80, shown as..

sqrt80
sqrt(4*4*5)
2*2sqrt5
4sqrt5

then we divide the powers by 2, if they're even, or if they're odd, subtract one (which will stay inside the radical) then divide by 2

for x:
sqrt(x^7)
sqrt(x^6*x
x^3sqrtx

and for y:
sqrt(y^5)
sqrt(y^4*y)
y^2sqrty

then multiply the answers together, and there you have it