# What is the simplified radical form of (3sqrt2+3sqrt6+3sqrt2)/2?

$\frac{3 \sqrt{2} + 3 \sqrt{6} + 3 \sqrt{2}}{2}$
$= \frac{6 \sqrt{2} + 3 \sqrt{6}}{2}$
$= \frac{\left(3 \sqrt{2}\right) \left(2 + \sqrt{3}\right)}{2}$
$= \frac{3 \left(2 + \sqrt{3}\right)}{\sqrt{2}}$