Question

What is the slope of a line perpendicular to the line whose equation is `5x+3y=8`?

Answer 1

If a line has slope `=m`
then the slope of a line perpendicular to it is `(-1/m)`

Rewrite `5x+3y=8` in a slope-offset format

`y=-5/3x+8/3`
So the given equation has a slope of `(-5/3)`
and
a line perpendicular to it has a slope of `(3/5)`