# What is the slope of a line perpendicular to the line whose equation is 5x+3y=8?

If a line has slope $= m$
then the slope of a line perpendicular to it is $\left(- \frac{1}{m}\right)$
Rewrite $5 x + 3 y = 8$ in a slope-offset format
$y = - \frac{5}{3} x + \frac{8}{3}$
So the given equation has a slope of $\left(- \frac{5}{3}\right)$
a line perpendicular to it has a slope of $\left(\frac{3}{5}\right)$