# What is the slope of a line that is perpendicular to C(13, 2), D(15, -5)?

##### 1 Answer
Jun 10, 2015

Any line perpendicular to C(13,2), D(15,-5) has a slope of $\frac{2}{7}$

#### Explanation:

The line segment joining C(13,2), D(15,-5)
has a slope of $\frac{\Delta y}{\Delta x} = \frac{2 - \left(- 5\right)}{13 - 15} = - \frac{7}{2}$

If a line has a slope of $m$ any line perpendicular to it has a slope of $\left(- \frac{1}{m}\right)$