# What is the slope of any line perpendicular to the line passing through (-14,25) and (0,20)?

$\frac{14}{5}$
First find the slope of the two given points and that is the change in $y$-coordinates over the change in $x$-coordinates.
$\frac{20 - 25}{0 - \left(- 14\right)} = - \frac{5}{14}$
Therefore, the slope of the line by the two given points is $- \frac{5}{14}$ and any arbitrary line perpendicular to this slope would be the negative reciprocal, which is $\frac{14}{5}$