Question

What is the slope of any line perpendicular to the line passing through `(-26,2)` and `(-12,5)`?

Answer 1

The slope is `m = 3/14`
the perpendicular slope would be
`m = -14/3`

Explanation:

The slope a line that is perpendicular to a given line would be the inverse slope of the given line

`m = a/b` the perpendicular slope would be `m =-b/a`

The formula for the slope of a line based upon two coordinate points is

`m = (y_2-y_1)/(x_2-x_1)`

For the coordinate points `(-26,2) and (-12,5)`
`x_1 = -26`
`x_2 = -12`
`y_1 = 2`
`y_2 = 5`

`m = (5-2)/(-12-(-26))`

`m = 3/14`

The slope is `m = 3/14`
the perpendicular slope would be
`m = -14/3`