What is the slope of any line perpendicular to the line passing through #(3,12)# and #(-5,17)#?

1 Answer
Dec 31, 2015

Of any line ?

#A = (3,12) # #B = (-5,17)#

#vec(AB) = (-5-3,17-12) = (-8,5)#

The equation of the line directed by this vector is #P = 5x+8y=0#

Now imagine all the couple which are solutions to this equation

#lambda = (x_0,x_1,...x_n;y_0,y_1,...y_n)#

Note that #A,B in lambda#

Now imagine an arbitrary coordinate #M(x,y)# It can be anything

#vec(lambdaM)# is perpendicular to #P# if and only if it is perpendicular to #vec(AB)# and it is perpendicular to #vec(AB)# if and only if #vec(lambdaM)*vec(AB) = 0#

#-8(x-x_0)+5(y-y_0) = 0# if you take the point #A# you have

#-8(x-3)+5(y-12) = 0#

if you take the point #B# you have :

#-8(x+5)+5(y-17) = 0#

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