What is the slope of any line perpendicular to the line passing through (-3,17) and (2,10)?

The slope$\left({m}_{2}\right)$ of the perpendicular line is $\frac{5}{7}$
The slope $\left({m}_{1}\right)$ of the lne passing through $\left(- 3 , 17\right) \mathmr{and} \left(2 , 10\right) i s \frac{10 - 17}{2 + 3} = - \frac{7}{5}$ Hence the slope$\left({m}_{2}\right)$ of the perpendicular line is $\frac{- 1}{- \frac{7}{5}} = \frac{5}{7}$.Since the condition of perpendicular lines is ${m}_{1} \cdot {m}_{2} = - 1$[Ans]