# What is the slope of any line perpendicular to the line passing through (3,8) and (-2,-15)?

Mar 17, 2016

#### Answer:

$- \frac{5}{23}$

#### Explanation:

The slope of the line joining $\left({x}_{1} , {y}_{1}\right) \mathmr{and} \left({x}_{2} , {y}_{2}\right) = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$.

The slope of the perpengicular line is the negarive reciprocal.

The slope of the given line is $\frac{23}{5}$and irs negative reciprocal is $- \frac{5}{23}$.