What is the slope of any line perpendicular to the line passing through #(-6,17)# and #(2,18)#?

2 Answers
Mar 26, 2016

Answer:

#-8#

Explanation:

First, we need to find the slope of the line passing through #(-6,17)# and #(2,18)#. The slope is;

#(18-17)/(2-(-6)) = 1/8#

If we multiply the slope of any line with #-1# and then get its reciprocal, we find the slope of the line which is perpendicular to it.

So;

#1/8.-1=-1/8# its reciprocal #-># #-8#

Mar 26, 2016

Answer:

slope = -8

Explanation:

The first step is to calculate the gradient ( slope) of the line passing through the 2 given points using the #color(blue)" gradient formula " #

# m = (y_2 - y_1)/(x_2 - x_1) #

where # (x_1,y_1)" and " (x_2,y_2)" are 2 coordinate points "#

let # (x_1,y_1)=(-6,17)" and " (x_2,y_2)=(2,18) #

# rArr m = (18-17)/(2-(-6)) = 1/8 #

If 2 lines with gradients , say #m_1" and " m_2" are perpendicular"#

Then # m_1 xx m_2 = -1 #

#rArr 1/8xxm_2 = -1 rArr m_2 =-1/(1/8) = -8 #