Question

What is the slope of any line perpendicular to the line passing through `(8,-6)` and `(-7,1)`?

Answer 1

For a line to be perpendicular to a given line their slopes have to multiply to give a result of `-1`

Explanation:

So we first get the slope of the line:
(btw: `Delta` means difference)

`m_1=(Deltay)/(Deltax)=(1-(-6))/(-7-8)=7/-15=-7/15`

Now the perpendicular line will have a slope of:

`m_2=+15/7` because `(-7/15)*(+15/7)=-1`