What is the slope of the line normal to the tangent line of #f(x) = cscx+cos^2(5x-pi) # at # x= (11pi)/8 #?
This may be a wildly constructed problem, but here's my attempt to answer it:
To determine the slope of any tangent line, we need the derivative of the curve. For this problem:
the slope of the tangent line at that point is:
Since the lines are perpendicular, the slope of the normal line is the negative reciprocal of the slope of the tangent: