What is the slope of the line normal to the tangent line of f(x) = secx-cos3x at x= (pi)/12 ?
1 Answer
Slope of normal:
Explanation:
since we know that the derivative of
if
therefore,
therefore, the point at which the normal passes is
^ this simplifies to:
therefore, the slope of the tangent is
since the slope of the normal is the negative reciprocal to the slope of a line, the slope of the normal will be:
Slope of normal:
Side note:
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I simplified a few things and skipped those steps purposely so that this question doesn't run forever
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I would say the hardest part about this question would be the simplification such as figuring out what
tan(pi/12) is or whatsec(pi/12) is