# What is the slope of the line normal to the tangent line of f(x) = xe^(x-1)+x^3  at  x= 2 ?

Slope of normal line to the tangent would be -1/ (3e+12
Slope of tangent line is $f ' \left(x\right) = x {e}^{x - 1} + {e}^{x - 1} + 3 {x}^{2}$
Slope of normal line to the tangent would be -1/ (3e+12