# What is the slope of the line perpendicular to 2y= -6x +8?

Jul 2, 2016

$+ \frac{1}{3}$

#### Explanation:

Change the equation into standard form first (÷2):

$y = - 3 x + 4$

The gradient is -3 - better written as $- \frac{3}{1}$

The gradients of perpendicular lines are negative reciprocals of each other.

The required gradient is $+ \frac{1}{3}$

A check is that their product should be -1

${m}_{1} \times {m}_{2} = - \frac{3}{1} \times \frac{1}{3} = - 1$