# What is the slope of the line perpendicular to the line y = 2/3x - 12?

I found: slope$= - \frac{3}{2}$
The slope ${m}_{1}$ of the perpendicular to a line of slope $m$ will be:
${m}_{1} = - \frac{1}{m}$
In your case the given line has slope $m = \frac{2}{3}$ (the coefficient of $x$), so the perpendicular will have slope:
${m}_{1} = - \frac{3}{2}$