# What is the slope of the line perpendicular to y=2/7*x-13 ?

Jun 20, 2016

$- \frac{7}{2}$
The original equation is of form $y = m x + c$ where m is the gradient.
The gradient of a line perpendicular to this is $\left(- 1\right) \times \frac{1}{m}$
So for your question we have $\left(- 1\right) \times \left(1 \div \frac{2}{7}\right) = - \frac{7}{2}$