# What is the slope of the line perpendicular to  y=-6/11x -5 ?

It is ${m}_{2} = \frac{11}{6}$
If ${m}_{1}$ and ${m}_{2}$ are the slopes of two lines in order to be
${m}_{1} \cdot {m}_{2} = - 1$
hence in our case $\left(- \frac{6}{11}\right) \cdot {m}_{2} = - 1 \implies {m}_{2} = \frac{11}{6}$