# What is the slope of the line perpendicular to  y=-8/5x-2 ?

Feb 14, 2016

$\frac{5}{8}$

#### Explanation:

the equation of a straight line , y = mx + c , where m represents the gradient (slope) and c , the y-intercept , is useful in that m and c may be extracted from it.

$y = - \frac{8}{5} x - 2 \textcolor{b l a c k}{\text{ is in this form }}$

here then $m = - \frac{8}{5}$

If 2 lines are perpendicular , then the product of their gradients is - 1.
let gradient of perpendicular line be ${m}_{1}$

then ${m}_{1} \times - \frac{8}{5} = - 1 \Rightarrow {m}_{1} = \frac{- 1}{-} \left(\frac{8}{5}\right) = - 1 \times - \frac{5}{8} = \frac{5}{8}$