What is the slope of the line tangent to the graph of #y=ln(x^2)# at #x=e^2#?
1 Answer
Jul 30, 2017
Explanation:
#•color(white)(x)dy/dx=m_(color(red)"tangent")" at x = a"#
#•color(white)(x)d/dx(lnx)=1/x#
#"differentiate using the "color(blue)"chain rule"#
#•color(white)(x)d/dx(ln(f(x)))=1/f(x)xxf'(x)#
#y=ln(x^2)#
#rArrdy/dx=1/x^2xxd/dx(x^2)#
#color(white)(rArrdy/dx)=2/x#
#x=e^2tody/dx=2/e^2#
