What is the slope of the line that passes through (3 ,5) and (-3,-5) ?

2 Answers
Apr 10, 2018

#"slope "=5/3#

Explanation:

#"to calculate the slope m use the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(3,5)" and "(x_2,y_2)=(-3,-5)#

#rArrm=(-5-5)/(-3-3)=(-10)/(-6)=10/6=5/3#

Apr 10, 2018

#y=5/3x+c#, where the slope is #5/3# and the #y# intercept is #+2#

Explanation:

The slope of a line can be found out using:

Change in #y# // change in #x#

Where the first coordinate is #x#, and the second coordinates are #y#

#therefore# #3 -> -6# you have to #-6#

#therefore# #5 -> -5# you have to #-10#

#therefore# #-> (-10)/-6 -> 5/3# when dividing by #3#.

Remember a negative divided by a negative gets a positive.

If wanting to find the full equation, we have to find the #y# intercept as this is in the form:

#y=mx+c# where #m# is the gradient #(5/3)# and #c# is the #y# intercept.

So far we have:

#y=5/3x+c#

We can substitute in the #y# value, and the slope.

Using the coordinates #(3,5)#

#5=5/3 xx 3+c#

#5=3+c#

#therefore# #c=2#

using #y=mx+c#

#-> y=5/3x+2#