What is the solution of #1/2 |2x+3|-1>1#?

1 Answer
Binayaka C.
Oct 3, 2016

Solution: #x < -7/2 or x > 1/2 #. In interval notation: #( -oo, -7/2) uu (1/2 , oo)#

Explanation:

1) #1/2|2x+3| -1 > 1 or 1/2|2x+3| > 2 or |2x+3| > 4 or 2x+3 > 4 or 2x > 1 or x > 1/2 # OR
2) #1/2|2x+3| -1 > 1 or 1/2|2x+3| > 2 or |2x+3| > 4 or 2x+3 < -4 or 2x < -7 or x < -7/2 #
Solution: #x < -7/2 or x > 1/2 #. In interval notation:#( -oo, -7/2) uu (1/2 , oo)#[Ans]

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