What is the solution set for #5/3-2/x=8x# if #x!=0#?

1 Answer
Aug 7, 2018

#x = (5 +- sqrt(551)i)/48#

Explanation:

First, add a 1 as a denominator for 8x:

#5/3 - 2/x = (8x)/1#

Then, find the GCF (Greatest Common Denominator), which in this case is 3x.

#(5x)/(3x) - 6/(3x) = (24x^2)/(3x)#

Next, since there is an equal sign, we can just eliminate the 3x from the denominator and have a simple equation:

#5x - 6 = 24x^2#

Put them all on 1 side.

#24x^2 - 5x + 6 = 0#

Do the quadratic formula:

#x = -b +- (sqrt(b^2-4ac))/(2a)#

#x = 5 +- (sqrt(25 - 4(24)(6)))/48#

Solve for x:

#x = (5 +- sqrt(551)i)/48#